[sbopkg-users] bash completion
Sergey V.
sftp.mtuci at gmail.com
Fri Jan 7 23:51:27 UTC 2011
Hello all!
Here is current version of bash completion script for sbopkg (attached).
Also actual version is available on github [1].
Any comments or suggestions are welcome.
regards, Sergey
[1] https://github.com/sftp/bash-completion/blob/sftp/completions/sbopkg
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# -*- sh -*-
# bash completion for sbopkg tool
#
# (c) Igor Murzov <igor at gplsoft.org>
# (c) Sergey V. <sftp.mtuci at gmail.com>
have sbopkg &&
_sbopkg()
{
COMPREPLY=()
local cur prev
_get_comp_words_by_ref cur prev
if [[ "$cur" == -* ]]; then
COMPREPLY=( $( compgen -W '-b -c -d -e -f -g -h -i -k -l \
-o -P -p -q -R -r -s -u -V -v' -- "$cur" ) )
return 0
fi
case $prev in
-e)
COMPREPLY=( $( compgen -W 'ask continue stop' -- "$cur" ) )
return 0
;;
-f)
_filedir
return 0
;;
-d)
_filedir -d
return 0
;;
-V)
COMPREPLY=( $( compgen -W "? \
`sbopkg -V ? 2>&1 | cut -s -f1`" -- "$cur" ) )
return 0
;;
-i|-b)
;;
*)
return 0
;;
esac
local config="/etc/sbopkg/sbopkg.conf"
local words
_get_comp_words_by_ref words
for (( i=${#words[@]}-1; i>0; i-- )); do
if [[ ${words[i]} == '-f' ]]; then
config="${words[i+1]}"
break
fi
done
if [ ! -r "$config" ]; then
return 0
fi
. $config
for (( i=1; i<${#words[@]}; i++ )); do
case "${words[i]}" in
'-V')
REPO_NAME="${words[i+1]%%/*}"
REPO_BRANCH="${words[i+1]#*/}"
;;
'-d')
REPO_ROOT="${words[i+1]}"
;;
esac
done
if [ ! -r "$REPO_ROOT/$REPO_NAME/$REPO_BRANCH/SLACKBUILDS.TXT" ]; then
return 0
fi
COMPREPLY=( $( grep "^SLACKBUILD NAME: $cur" \
$REPO_ROOT/$REPO_NAME/$REPO_BRANCH/SLACKBUILDS.TXT | cut -f3- -d\ )
$( (cd $QUEUEDIR; ls $cur*.sqf 2> /dev/null) ) )
return 0
} && complete -F _sbopkg sbopkg -o plusdirs
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